dirección espiral de la dirección en sentido horario js
var input = [[1, 2, 3, 4],
[5, 6, 7, 8],
[9, 10, 11, 12],
[13, 14, 15, 16]];
var spiralTraversal = function(matriks){
var result = [];
var goAround = function(matrix) {
if (matrix.length == 0) {
return;
}
// right
result = result.concat(matrix.shift());
// down
for (var j=1; j < matrix.length - 1; j++) {
result.push(matrix[j].pop());
}
// bottom
result = result.concat(matrix.pop().reverse());
// up
for (var k=matrix.length -2; k > 0; k--) {
result.push(matrix[k].shift());
}
return goAround(matrix);
};
goAround(matriks);
return result;
};
var result = spiralTraversal(input);
console.log('result', result);
Udit Singh