js bucle a través de la matriz hacia atrás
let arr = [1, 2, 3];
arr.slice().reverse().forEach(x => console.log(x))
Friendly Hawk
let arr = [1, 2, 3];
arr.slice().reverse().forEach(x => console.log(x))var arr = [1, 2, 3, 4, 5];
for (var i = arr.length - 1; i >= 0; i--) {
console.log(arr[i]);
}const array = ['alpha', 'beta', 'gamma'];
array.reduceRight((_, elem) => console.log(elem), null);
Run code snippetvar arr = [1, 2, 3, 4, 5];
for (var i = arr.length - 1; i >= 0; i--) {
arr[i]
}let arr = [1, 2, 3];
arr.slice().reverse().forEach(x => console.log(x))const array = ['alpha', 'beta', 'gamma'];
array.reduceRight((_, elem) => console.log(elem), null);