matriz de bucle de JavaScript al revés
let arr = [1, 2, 3];
arr.slice().reverse().forEach(x => console.log(x))
Friendly Hawk
let arr = [1, 2, 3];
arr.slice().reverse().forEach(x => console.log(x))var arr = [1, 2, 3, 4, 5];
for (var i = arr.length - 1; i >= 0; i--) {
console.log(arr[i]);
}let arr = [1, 2, 3];
arr.slice().reverse().forEach(x => console.log(x))
Run code snippetfor (i = array.length - 1; i >= 0; i--) {
code
}
var arr = [1, 2, 3, 4, 5];
for (var i = arr.length - 1; i >= 0; i--) {
console.log(arr[i]);
}var arr =[1,2,3]
for(let element of arr.reverse()){
console.log(element)
}