matriz de bucle js al revés
let arr = [1, 2, 3];
arr.slice().reverse().forEach(x => console.log(x))
Friendly Hawk
let arr = [1, 2, 3];
arr.slice().reverse().forEach(x => console.log(x))var arr = [1, 2, 3, 4, 5];
for (var i = arr.length - 1; i >= 0; i--) {
console.log(arr[i]);
}var array = [1,2,3,4];
//array stores a set of arguments, which in this case are all numbers
var totalArguments = array.length;
//totalArguments stores the total number of arguments that are in the array
//To get the arguments of the array to display in reverse we will -
// first have to subract 1 to totalArguments because to access the -
// arguments of an array they start from 0 to the total number of -
// arguments-1, which in this case would be totalArgumenst = 4 -
// 4 - 1 = 3 , so we are going to display 0 to 3 with a for loop
for (var i = totalArguments - 1 ; i >= 0 ; i--) {
console.log(array[i]);
}let arr = [1, 2, 3];
arr.slice().reverse().forEach(x => console.log(x))for (var i = arr.length - 1; i >= 0; i--) {
console.log(arr[i]);
}var arr = [1, 2, 3, 4, 5];
arr.reduceRight((_, item) => console.log(item), null);