“SQL usando declaraciones preparadas” Código de respuesta

SQL usando declaraciones preparadas

$sql = "INSERT INTO Users (first_name, last_name, email) VALUES (?, ?, ?)";

mysqli_stmt_bind_param($sql, "sss", $first_name, $last_name, $email);

$first_name = "Harry";
$last_name = "Potter";
$email = "[email protected]";

mysqli_stmt_execute($stmt);