“la diferencia entre los valores en SQL” Código de respuesta

la diferencia entre los valores en SQL

SELECT 	
city,
	year,
      population_needing_house,
      LAG(population_needing_house)
      OVER (PARTITION BY city ORDER BY year ) AS previous_year
      population_needing_house - LAG(population_needing_house)
 	OVER (PARTITION BY city ORDER BY year ) AS difference_previous_year
FROM 	housing
ORDER BY city, year