Url a origen python
from urllib.parse import urlparse
# from urlparse import urlparse # Python 2
parsed_uri = urlparse('http://stackoverflow.com/questions/1234567/blah-blah-blah-blah' )
result = '{uri.scheme}://{uri.netloc}/'.format(uri=parsed_uri)
print(result)
# gives
'http://stackoverflow.com/'
Worried Walrus