Convertir la lista de cuerdas a Ints Python
test_list = ['1', '4', '3', '6', '7']
int_list = [int(i) for i in test_list]
EDestroyer
test_list = ['1', '4', '3', '6', '7']
int_list = [int(i) for i in test_list]test_list = list(map(int,test_list))num = [1, 2, 3, 4]
s = [str(i) for i in num] # Converting integers into strings
result = str("".join(s)) # Join the string values into one string
print(result)# Basic syntax:
list_of_ints = [int(i) for i in list_of_strings]
# Example usage with list comprehension:
list_of_strings = ['2', '3', '47']
list_of_ints = [int(i) for i in list_of_strings]
print(list_of_ints)
--> [2, 3, 47]>>> example_string = '0, 0, 0, 11, 0, 0, 0, 0, 0, 19, 0, 9, 0, 0, 0, 0, 0, 0, 11'
>>> list(map(int, example_string.split(','))) # Python 3, in Python 2 the list() call is redundant
[0, 0, 0, 11, 0, 0, 0, 0, 0, 19, 0, 9, 0, 0, 0, 0, 0, 0, 11]
>>> [int(s) for s in example_string.split(',')]
[0, 0, 0, 11, 0, 0, 0, 0, 0, 19, 0, 9, 0, 0, 0, 0, 0, 0, 11]
results = [int(i) for i in results]