Convertir la lista de cuerdas a Ints Python
test_list = ['1', '4', '3', '6', '7']
int_list = [int(i) for i in test_list]
EDestroyer
test_list = ['1', '4', '3', '6', '7']
int_list = [int(i) for i in test_list]num = [1, 2, 3, 4]
s = [str(i) for i in num] # Converting integers into strings
result = str("".join(s)) # Join the string values into one string
print(result)>>> example_string = '0, 0, 0, 11, 0, 0, 0, 0, 0, 19, 0, 9, 0, 0, 0, 0, 0, 0, 11'
>>> list(map(int, example_string.split(','))) # Python 3, in Python 2 the list() call is redundant
[0, 0, 0, 11, 0, 0, 0, 0, 0, 19, 0, 9, 0, 0, 0, 0, 0, 0, 11]
>>> [int(s) for s in example_string.split(',')]
[0, 0, 0, 11, 0, 0, 0, 0, 0, 19, 0, 9, 0, 0, 0, 0, 0, 0, 11]
integers = [1, 2, 3]
strings = [str(integer) for integer in integers]
a_string = "". join(strings)
an_integer = int(a_string)
print(an_integer)Use the map function (in Python 2.x):
results = map(int, results)
In Python 3, you will need to convert the result from map to a list:
results = list(map(int, results))results = [int(i) for i in results]