# The pop function, without an input, defaults to removing
# and returning the last item in a list.
myList = [1, 2, 3, 4, 5]
myList.pop()
print(myList)
# You can also do this without returning the last item, but it is
# much more complicated.
myList = [1, 2, 3, 4, 5]
myList.remove(myList[len(myList)-1])
print(myList)record = record[:-1]l = list(range(1,5))
l = test_list[: len(test_list) - 2] # Remove the last 3 items from a list
x = [1, 2, 3, 4, 5]
for i in range(3): x.pop()from functools import cmp_to_key
sorted(mylist, key=cmp_to_key(lambda item1, item2: fitness(item1) - fitness(item2)))from time import time
q = input('What do you want to type? ')
a = ' '
record = []
while a != '':
start = time()
a = input('Type: ')
end = time()
v = end-start
record.append(v)
if a == q:
print('Time taken to type name: {:.2f}'.format(v))
else:
break
for i in record:
print('{:.2f} seconds.'.format(i))