Cómo imprimir error en intento excepto python
try:
# some code
except Exception as e:
print("ERROR : "+str(e))
Jenova
try:
# some code
except Exception as e:
print("ERROR : "+str(e))
try:
someFunction()
except Exception as ex:
template = "An exception of type {0} occurred. Arguments:\n{1!r}"
message = template.format(type(ex).__name__, ex.args)
print (message)
>>> def catch():
... try:
... asd()
... except Exception as e:
... print e.message, e.args
...
>>> catch()
global name 'asd' is not defined ("global name 'asd' is not defined",)
import traceback
dict = {'a':3,'b':5,'c':8}
try:
print(dict[q])
except:
traceback.print_exc()
# This will trace you back to the line where everything went wrong.
# So in this case you will get back line 5
def FileCheck(fn):
try:
open(fn, "r")
return 1
except IOError:
print "Error: File does not appear to exist."
return 0
result = FileCheck("testfile")
print result
UsageError: Cell magic `%%mysql` not found.