Dejar A = { L ∣ Les un contador y L¯ también es un contador }A={L∣Lis one-counter and L¯ is also one-counter}A= \{L \mid L \;\text{is one-counter and \(\bar{L}\) is also one-counter} \} Claramente,Un contador determinista ⊆ ADeterministic one-counter⊆A\text{Deterministic one-counter} \subseteq...