“Container con la mayoría de las pitones de agua leetcode” Código de respuesta

Container con la mayoría de las pitones de agua leetcode

def maxArea(height: List[int]) -> int:
    # This variable will store the maximum area
    max_area = -maxsize
    # Left and right pointers
    left = 0
    right = len(height) - 1
    # Loop until the two pointers meet
    while left < right:
        # Shorter of the two lines
        shorter_line = min(height[left], height[right])
        max_area = max(max_area, shorter_line * (right - left))
        # If there is a longer vertical line present
        if height[left] < height[right]:
            left += 1
        else:
            right -= 1
    return max_area