Números de suma de Bash
num1=1232
num2=24
num3=444
sum=$((num1+num2+num3))
echo $sum # prints 1700
Error Destroyer-47
num1=1232
num2=24
num3=444
sum=$((num1+num2+num3))
echo $sum # prints 1700
#Just use following structure for summing up varibles:
sum=$((var1 + var2))
#For float numbers use next instruction:
sum=$(bc <<< $var1'+'$var2)