Python encontrar permutaciones de operadores entre cada dígito en una cadena dada de dígitos dará como resultado una respuesta particular
from itertools import product
import re
def groupPatterns(count,pattern=None):
arr = pattern or "X"*count
if len(arr) < 2 : return [arr]
result = []
for mid in range(1,len(arr)):
leftPattern = groupPatterns(count,arr[:mid])
rightPattern = groupPatterns(count,arr[mid:])
for left,right in product(leftPattern,rightPattern):
result += [left + right]
if len(left) > 1 : result += ["(" + left + ")" + right]
if len(right) > 1 : result += [left + "(" + right + ")"]
if len(left) > 1 and len(right) > 1:
result += ["(" + left + ")(" + right + ")"]
if pattern: return result # recursion
patterns = [] # final, add "+" between X value placeholders or groups
for pat in sorted(set(result),key=lambda x:len(x)):
pat = re.sub("X(?=X)", r"X+", pat) # XX --> X+X
pat = re.sub("X\(", r"X+(", pat) # X( --> X+(
pat = re.sub("\)X", r")+X", pat) # )X --> )+X
pat = re.sub("\)\(", r")+(", pat) # )( --> )+(
patterns.append(pat)
return patterns
AttributeError: 'Me' object has no attribute 'Funny'