Lista de archivos en el directorio Python
import os
print(os.listdir('/path/to/folder/to/list'))
Blushing Badger
import os
print(os.listdir('/path/to/folder/to/list'))from os import listdir
from os.path import isfile, join
onlyfiles = [f for f in listdir(mypath) if isfile(join(mypath, f))]import os
for root, dirs, files in os.walk("."):
for filename in files:
print(filename)
import glob
print(glob.glob("/home/adam/*"))import os
def get_filepaths(directory):
"""
This function will generate the file names in a directory
tree by walking the tree either top-down or bottom-up. For each
directory in the tree rooted at directory top (including top itself),
it yields a 3-tuple (dirpath, dirnames, filenames).
"""
file_paths = [] # List which will store all of the full filepaths.
# Walk the tree.
for root, directories, files in os.walk(directory):
for filename in files:
# Join the two strings in order to form the full filepath.
filepath = os.path.join(root, filename)
file_paths.append(filepath) # Add it to the list.
return file_paths # Self-explanatory.
# Run the above function and store its results in a variable.
full_file_paths = get_filepaths("/Users/johnny/Desktop/TEST")path = "C:\code\"
import glob
txtfiles = []
for file in glob.glob(path + "\\*.m4a"):
txtfiles.append(file)
for item in txtfiles:
print(item)