“diccionario ordenado” Código de respuesta

Diccionario ordenado de Python

from collections import OrderedDict

# Remembers the order the keys are added!
x = OrderedDict(a=1, b=2, c=3)
Delta Sierra

Python Ordereddict

>>> # regular unsorted dictionary
>>> d = {'banana': 3, 'apple': 4, 'pear': 1, 'orange': 2}

>>> # dictionary sorted by key
>>> OrderedDict(sorted(d.items(), key=lambda t: t[0]))
OrderedDict([('apple', 4), ('banana', 3), ('orange', 2), ('pear', 1)])

>>> # dictionary sorted by value
>>> OrderedDict(sorted(d.items(), key=lambda t: t[1]))
OrderedDict([('pear', 1), ('orange', 2), ('banana', 3), ('apple', 4)])

>>> # dictionary sorted by length of the key string
>>> OrderedDict(sorted(d.items(), key=lambda t: len(t[0])))
OrderedDict([('pear', 1), ('apple', 4), ('orange', 2), ('banana', 3)])
rebellion

Orden de orden

# A Python program to demonstrate working of OrderedDict
from collections import OrderedDict
 
print("This is a Dict:\n")
d = {}
d['a'] = 1
d['b'] = 2
d['c'] = 3
d['d'] = 4
 
for key, value in d.items():
    print(key, value)
 
print("\nThis is an Ordered Dict:\n")
od = OrderedDict()
od['a'] = 1
od['b'] = 2
od['c'] = 3
od['d'] = 4
 
for key, value in od.items():
    print(key, value)
Phuong Anh Dang

diccionario ordenado

# ordered dictionary
#Regular Dictionary
d = {'apple':1, 'oranges':2, 'bananas':3}
d['grapes'] = 4
print(d)

#Output:
# {'apple': 1, 'bananas': 3, 'grapes': 4, 'oranges': 2}

#Ordered Dictionary
from collections import OrderedDict
d = OrderedDict({'apple':1, 'oranges':2, 'bananas':3})
d['grapes'] = 4
print(d)

# OrderedDict([('apple', 1), ('oranges', 2), ('bananas', 3), ('grapes', 4)])
Impossible Impala

Python Collections to Dictionary

list = ["a","c","c","a","b","a","a","b","c"]
cnt = Counter(list)
od = OrderedDict(cnt.most_common())
for key, value in od.items():
    print(key, value)
Cheerful Cormorant

Python de diccionario ordenado

>>> # regular unsorted dictionary
>>> d = {'banana': 3, 'apple': 4, 'pear': 1, 'orange': 2}

>>> # dictionary sorted by key
>>> OrderedDict(sorted(d.items(), key=lambda t: t[0]))
OrderedDict([('apple', 4), ('banana', 3), ('orange', 2), ('pear', 1)])

>>> # dictionary sorted by value
>>> OrderedDict(sorted(d.items(), key=lambda t: t[1]))
OrderedDict([('pear', 1), ('orange', 2), ('banana', 3), ('apple', 4)])

>>> # dictionary sorted by length of the key string
>>> OrderedDict(sorted(d.items(), key=lambda t: len(t[0])))
OrderedDict([('pear', 1), ('apple', 4), ('orange', 2), ('banana', 3)])
Vast Vendace

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