Subiendo escaleras
var climbStairs = function(n) {
const m =[1,1,2];
for(let i=3; i<=n;i++){
m[i] = m[i-1]+m[i-2]
}
return m[n]
};
ABS
var climbStairs = function(n) {
const m =[1,1,2];
for(let i=3; i<=n;i++){
m[i] = m[i-1]+m[i-2]
}
return m[n]
};// Key intuition - the # of unique ways of reaching n depends on
// how many ways you can reach step n - 1 PLUS step n - 2
// n = n - 1 + n - 2
export function solution(n: number) {
let one = 1 // # of ways you can get to n - 1
let two = 1 // # of ways you can get to n - 2
// traverse and calculate the new values for n - 1 and n - 2
for (let i = 0; i < n - 1; i++) {
let temp = one // one is currently n - 1
// this moves n - 1 up to n (n = n - 1 + n - 2)
one = one + two
// this moves n - 2 up to n - 1
two = temp
}
return one
}