Encuentre el número de elementos comunes en dos matrices de pitón
len([x for x in list1 if x in list2])
Stranger danger
len([x for x in list1 if x in list2])x = {2, 3, 5, 6}
y = {1, 2, 3, 4}
z = x.intersection(y)
# using numpy
import numpy as np
a = np.array([1,2,3,2,3,4,3,4,5,6])
b = np.array([7,2,10,2,7,4,9,4,9,8])
# using intersect1d
print(np.intersect1d(a,b))
# output
# [2 4]