Python hoy - 1 día
from datetime import datetime, timedelta
yesterday = datetime.today() - timedelta(days = 1 )
MzanziLegend
from datetime import datetime, timedelta
yesterday = datetime.today() - timedelta(days = 1 )from datetime import datetime, timedelta
d = datetime.today() - timedelta(days=days_to_subtract)
import datetime
from datetime import timedelta
d = int(input('enter the day: '))
m = int(input('enter the month: '))
y = int(input('enter the year: '))
today = datetime.date(y, m, d)
tom = today + timedelta(days=1)
print('next day is', tom) date = int(input('enter the date: '))
month = int(input('enter the month: '))
year = int(input('enter the year: '))
x = (1, 3, 5, 7, 10)
y = (4, 6, 8, 9, 11)
if month in x and date == 31:
month = month + 1
date = 1
elif month in x and date < 31:
date = date + 1
elif month in y and date == 30:
month = month + 1
date = 1
elif month in y and date < 31:
date = date + 1
elif month == 2 and date == 28 or date == 29:
month = month+1
date = 1
elif month == 2 and date < 29:
date = date+1
elif month == 12 and date < 31:
date = date + 1
elif month == 12 and date == 31:
month = 1
date = 1
year = year + 1
print('%02d-' % date, '%02d-' % month, '%02d' % year)