(parent-dir "/home/sk/parent/ab.el")
da
"/home/sk/parent"
entonces,
(parent-dir "/home/sk/parent")
da
"/home/sk"
¿Alguna función de elisp parent-dirque proporciona la ruta base para la ruta del archivo y la ruta del directorio?
file-name-directory hace lo que pides.
Sin embargo, (file-name-directory "/home/sk/parent/")(con una barra inclinada final) devuelve el mismo directorio, no su padre.
Esto hace lo que supongo que realmente quieres:
(file-name-directory (directory-file-name "/home/sk/parent/ab.el")) ; => "/home/sk/parent/"
(file-name-directory (directory-file-name "/home/sk/parent/")) ; => "/home/sk/"
(file-name-directory (directory-file-name "/home/sk/parent")) ; => "/home/sk/"
Y la biblioteca Dired + usa esta función:
(defun diredp-parent-dir (file &optional relativep)
"Return the parent directory of FILE, or nil if none.
Optional arg RELATIVEP non-nil means return a relative name, that is,
just the parent component."
(let ((parent (file-name-directory (directory-file-name (expand-file-name file))))
relparent)
(when relativep
(setq relparent (file-name-nondirectory (directory-file-name parent))))
(and (not (equal parent file)) (or relparent parent))))
(defun parent-directory (dir)
(unless (equal "/" dir)
(file-name-directory (directory-file-name dir))))