nombre de archivo de incremento de Python por 1

import glob
import re
import os


def main():
    # We want all files that are S00E0x
	for name in glob.glob('./*S0*'):
        # We want to find in the filename 'Exx' and increase xx by 1
		new_name = re.sub('(E)([0-9]{2})', increment, name)
		os.rename(name, new_name)


def increment(num):
    # Return the first match which is 'E'. Return the 2nd match + 1 which is 'x + 1'
	return num.group(1) + str(int(num.group(2)) + 1).zfill(2)


if __name__ == '__main__':
	main()
Defiant Dugong