tomar datos de archivo en PHP variable
I suppose you want to get the content generated by PHP, if so use:
$Vdata = file_get_contents('http://YOUR_HOST/YOUR/FILE.php');
Otherwise if you want to get the source code of the PHP file, its the same as
a .txt file:
$Vdata = file_get_contents('path/to/YOUR/FILE.php');
Lokesh003Coding