Cómo ordenar manualmente JavaScript
//This code was written by user Smiling Salmon, full credit goes to them
//(the code is written very neatly and compactly)
//I've added comments to each individual line incase you are a total
//JS noob such as myself, who has no idea how to read this.
//hopefully you find the following commented lines educational.
var done = false;
//prevents loop ending before the array is properly sifted through enough times
function sort (array) {
while (!done) {
done = true;
//this code is set in a way so that the biggest number will always go to the end of the array
//it does this by checking if the number listed before it in the array is bigger than the current
//number listed in the array.
//Therefore, i is set to 1 instead of 0 so that the code is able to check "is the number behind me bigger?"
for (var i = 1; i < array.length; i += 1) {
//compares item in list before current item to the current item
if (array[i - 1] > array[i]) {
//tells the program to continue looping because there is still a number out of place.
done = false;
//tmp is used to temporarily copy the value of the bigger number onto itself
var tmp = array[i - 1];
//the bigger number then becomes the current number
array[i - 1] = array[i];
//and the current number then becomes the number which was previously before it. (thanks tmp)
array[i] = tmp;
//the code will continue to push the bigger numbers to the front until the conditional
//no longer tells done to equal false, thus ending the looping and sorting the array.
}
}
}
}
var numbers = [12, 10, 15, 11, 14, 13, 16];
sort(numbers);
console.log(numbers);
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