“Cuenta de ocurrencias en siete enteros utilizando matrices de dimensiones de Java” Código de respuesta

Cuenta de ocurrencias en siete enteros utilizando matrices de dimensiones de Java

public static int count(int[] arr, int num) {
        int count = 0;
        for(int i = 0; i < arr.length; ++i) {   // go through all elements in array
            if(arr[i] == num) { // if num is found, increase count
                count++;    // increment count
            }
        }
        return count;   // return the count of number of occurrences of num in array
    }

    public static boolean checkIfElementAlreadyExists(int[] arr, int index) {
        for(int i = 0; i < index; ++i) {    // go through all elements in array
            if(arr[i] == arr[index]) {  // if item in index already exists in the array
                return true;    // then return true
            }
        }
        return false;   // if element at index does not previously occur, then return false
    }

    public static void main(String[] args) {
        Scanner in = new Scanner(System.in);
        int[] arr = new int[7];
        System.out.print("Enter seven numbers: ");
        for(int i = 0; i < arr.length; ++i) {
            arr[i] = in.nextInt();  // read 7 numbers into array
        }
        for(int i = 0; i < arr.length; ++i) {   // go through all elements
            if(!checkIfElementAlreadyExists(arr, i)) {  // if this element did not already appear before in the array
                System.out.printf("Number %d occurs %d times.\n", arr[i], count(arr, arr[i]));  // then print the number and the number of time it occurs in the array
            }
        }
    }
}