Pasar una matriz en una función c
void ins (int (*matrix)[100], int row, int column);
Adventurous Addax
void ins (int (*matrix)[100], int row, int column);
#include <stdio.h>
#include <stdlib.h>
#define ROWS 3
#define COLS 2
void fun1(int **, int, int);
int main()
{
int array_2D[ROWS][COLS] = { {1, 2}, {3, 4}, {5, 6} };
int n = ROWS;
int m = COLS;
fun1(array_2D, n, m);
return EXIT_SUCCESS;
}
void fun1(int **a, int n, int m)
{
int i, j;
for (i = 0; i < n; i++) {
for (j = 0; j < m; j++) {
printf("array[%d][%d]=%d\n", i, j, a[i][j]);
}
}
}#include <stdio.h>
#include <stdlib.h>
#define ROWS 3
#define COLS 2
void fun1(int (*)[COLS], int);
int main()
{
int array_2D[ROWS][COLS] = { {1, 2}, {3, 4}, {5, 6} };
int rows = ROWS;
/* works here because array_2d is still in scope and still an array */
printf("MAIN: %zu\n",sizeof(array_2D)/sizeof(array_2D[0]));
fun1(array_2D, rows);
return EXIT_SUCCESS;
}
void fun1(int (*a)[COLS], int rows)
{
int i, j;
int n, m;
n = rows;
/* Works, because that information is passed (as "COLS").
It is also redundant because that value is known at compile time (in "COLS"). */
m = (int) (sizeof(a[0])/sizeof(a[0][0]));
/* Does not work here because the "decay" in "pointer decay" is meant
literally--information is lost. */
printf("FUN1: %zu\n",sizeof(a)/sizeof(a[0]));
for (i = 0; i < n; i++) {
for (j = 0; j < m; j++) {
printf("array[%d][%d]=%d\n", i, j, a[i][j]);
}
}
}