CF 633B Explicación del problema trivial
#include<queue>
#include<stack>
#include<vector>
#include<math.h>
#include<stdio.h>
#include<numeric>//STL数值算法头文件
#include<stdlib.h>
#include<string.h>
#include<iostream>
#include<algorithm>
#include<functional>//模板类头文件
using namespace std;
const int INF=0x3f3f3f3f;
const int maxn=500100;
int m,cnt;
int num[maxn],a[maxn];
int fun(int n)
{
int ans=0;
while(n)
{
n/=5;
ans+=n;
}
return ans;
}
int main()
{
for(int i=0; i<maxn; i++)
a[i]=fun(i);
while(~scanf("%d",&m))
{
cnt=0;
int i;
for(i=0; i<maxn; i++)
{
if(a[i]==m)
{
num[cnt++]=i;
}
}
printf("%d\n",cnt);
if(cnt)
{
for(i=0; i<cnt; i++)
{
if(i) printf(" ");
printf("%d",num[i]);
}
printf("\n");
}
}
return 0;
}
#include <cmath>
#include <cstdio>
#include <cstring>
#include <iostream>
#include <algorithm>
using namespace std;
const int MAXN = 1e9;
int fun(int n)
{
int cnt = 0;
while(n)
{
n/=5;
cnt+=n;
}
return cnt;
}
int Two(int l, int r, int m)
{
int ans = 0;
while(r >= l)
{
int mid = (l + r) >> 1;
int res = fun(mid);
if(res < m)
l = mid + 1;
else if(res >= m)
{
r = mid - 1;
ans = mid;
}
}
return ans;
}
int main()
{
int m;
while(cin >> m)
{
int l = 1, r = MAXN;
int L = Two(l, r, m), R = Two(l, r, m+1);
if(L == 0 || fun(R-1) != m) cout << 0 << endl;
else
{
cout << R - L << endl;
for(int i = L; i <= R-1; i++)
{
if(i > L) cout << " ";
cout << i;
}
cout << endl;
}
}
return 0;
}
Determined Duck